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26 November 2010

Air Conditioning: direct expansion (DX) & chilled water systems



PAUL HAY Capital Projects


Air-Conditioning, part 2 of 2

Author:            Paul Hay
e-mail:              paul.hay@phcjam.com
profile:             www.linkedin.com/in/phcjam




1.0          CENTRAL SYSTEMS ARE COMPLEX


1.1            Central Systems comprise one or more large mechanical spaces

1.2       Sizable distribution trees are used.

1.3       Central Systems are generally Direct Expansion (DX) or Chilled Water systems.

1.4       Chilled water systems are marginally more efficient than DX systems.
            1.4.1   Chilled water systems cool water, instead of air, and passes it through heat exchangers to cool the air.
            1.4.2   Water treatment may be required to control corrosion and scaling.
            1.4.3   Chillers cool the building by removing heat from water which has passed through the evaporators.
            1.4.4   Cooling towers are installed in large systems to increase efficiency.
                        1.4.4.1            Water cooled systems pass water over the condensor coils.
                        1.4.4.2            The water may be recycled after cooling in an atmospheric cooling tower.
                        1.4.4.3            Water cools as it falls through the air.
                        1.4.4.4            Large blowers may also be used to increase cooling by forcing air through the falling water.

1.5       DX systems directly cools air and distributes it by air-handling units.
            1.5.1   Air-handling units can be combined with the cooling equipment or separate.
            1.5.2   When separate, air-handling units can be centrally located in a building or distributed on each floor.
            1.5.3   Central cooling and local air-distribution takes advantage of benefits attributed to both the central and local systems
            1.5.4   Distribution trees are large because air has low heat-capacity.

  

2.     CHILLED WATER SYSTEMS USE ALL-WATER OR AIR-AND-WATER


2.1       Chilled water systems are frequently used in the perimeter zones.

2.2       A two-pipe system is used for cooling alone

2.3       Chillers for 2-pipe systems occupy 0.2 - 1.0% of the gross floor area.

2.4       All-water fan-coil units can be located against an exterior wall.
            2.4.1   Units installed above a window are called “valence” units; and
            2.4.2   Units installed below a window are called “baseboard” units.

2.5       Air-and-water induction systems use two coils.
            2.5.1   Fresh air is de-humidified and cooled at one coil then supplied under pressure to nozzles in the induction unit;
            2.5.2   A small jet of air is propelled in a manner that induces air within the space to move along the current over the second coil; and
            2.5.3   Thermostats control the flow of water or “secondary” air.


2.6       Induction systems are well suited for multi-zone applications.
            2.6.1   They use high velocity constant volume air supply at each terminal.
            2.6.2   Only the volume of air required is used.
            2.6.3   2-pipe induction units occupy 0.5 - 1.5% of the gross floor area.   


3.0   ALL-AIR SYSTEMS REQUIRE MORE SPACE


3.1       Single-duct Variable-Air-Volume systems require smaller distribution trees.
            3.1.1   Air-handling units supply a cooled stream of air at normal velocity and pre-determined temperature.
            3.1.2   Automatic volume controls connected to a zones’ thermostat adjust the volume of air admitted.
            3.1.3   A zone needing more cooling received more air, and vice-versa.  

3.2       Size of Air-handling equipment and their rooms are smaller for lower rates of air flow.
            3.2.1   Fan speeds should be reduced so that temperature-sensitive thermostats will permit sufficient de-humidification to take place.
            3.2.2   EEBC-94 requirements different ventilation rates.
                        3.2.1.1            The ventilation rate for non-smoking occupants is 3.5 L/s.
                        3.2.1.2            The rate for smoking occupants is 11.8 L/s.
            3.2.3   Low-pressure ductwork is larger.

3.3       Cooling equipment for a low velocity single-zone system requires 0.2 - 1% of the gross floor area.  
                        
3.4       Air-handling units for a low velocity single-zone system require 2.2 - 3.5% of the gross floor area.
            3.4.1   Adequate space is required for maintenance.
            3.4.2   Rooms should be centrally located to minimize ductwork.

3.5       Air-handling room require careful detailing.
            3.5.1   Special acoustical treatment is required if rooms are adjacent to sound-sensitive areas (eg. Conference Rooms).
            3.5.2   Air-intake and exhaust should be located on different walls, where possible, or no closer than 3m apart when located on the same wall.
            3.5.3   Baffles may be used to provide the separation required.
                       


4.0   DUCTWORK NEEDS TO BE CO-ORDINATED


4.1       Ducts can be round, oval or rectangular.
            4.1.1   Round ducts are usually less expensive to fabricate and install, but require higher ceiling heights.
            4.1.2   Ducts are generally fabricated in galvanized steel.


Figure showing various arrangements of ductwork

Figure 1: Various Arrangements of Ductwork



4.2       Fiberglass ducts are lighter and competitively priced.
            4.2.1   Ducts are available in rigid and flexible round profiles.
            4.2.2   Fiberglass ductwork is generally unsuitable for hospitals because the breeding of micro-organisms is more pronounced on them.

4.3       For better circulation of air when cooling, air supply should be through the ceiling and return air through low wall or floor return-air grilles.

4.4       Ducts are hung from metal hangers, straps, lugs or brackets.

4.5       Supply ducts should have locking-type dampers in branch ducts for volume control.
            4.5.1   Dampers should be installed as far as possible from the outlet.
            4.5.2   Distribution system needs to be balanced and adjusted for proper performance.
            4.5.3   It is critical that pressure differentials between adjacent rooms of a hospital be maintained to prevent cross-contamination.

4.6       Economizer cycle is an arrangement of dampers and controls that permits cooler external air to replace return-air in the cooling cycle.

4.7       Air diffusers and grilles are common to central all-air systems.
            4.7.1   Diffusers come in a wide variety of styles, shapes and sizes ranging from bar-type grilles for walls, to round, rectangular and slot-shaped diffusers for ceilings.
            4.7.2   The choice of air-diffusers is largely dependent on the desired architectural effect.



FURTHER READING

            Mechanical and Electrical Equipment for Buildings, 8th edition, Benjamin Stein, John S. Reynolds, John Wiley & Sons Inc., USA, 1992
Construction Materials & Processes, Don G. Watson, McGrawHill Book Co., USA, 1978;
            Ramsey/Sleeper Architectural Graphic Standards, AIA, Robert T. Packard (ed), John Wiley & Sons Inc., USA, 1981;
Architectural Handbook, Alfred M. Kemper, John Wiley & Sons Inc., USA, 1979
Jamaica National Building Code, Volume 2: Energy Efficiency Building Code, Requirements and Guidelines, 1994, Joseph J. Deringer (ed.), Jamaica Bureau of Standards, Jamaica, 1995.
“The Well-Tempered Tropics”, Thomas Fisher, Progressive Architecture, pp. 98-103.

16 November 2010

OTTV: what it is and how to calculate it



PAUL HAY Capital Projects

            

Overall Thermal Transmission Value (OTTV)

Author:            Paul Hay
e-mail:              paul.hay@phcjam.com
profile:             www.linkedin.com/in/phcjam


1.0  WHAT IS OTTV?        

1.1            Overall Thermal Transmission Value (OTTV) is the measure of external heat-gain transmitted through a unit area of a building’s wall or roof;

1.2       OTTV is recorded in units of W/m2.

1.3       OTTV concerns conductive & radiative heat-gains transmitted through glazing and opaque components.

2.0  OTTV VARIABLES  


2.1       Equivalent Temperature Differential (TDeq) is the theoretical difference between outdoor and indoor temperatures that would result in a heat transfer equivalent to the effects of solar heat-gains, thermal storage and actual temperature difference on an opaque component, as a roof [unit = K];

2.2       Solar Factor (SF) is the average hourly value of solar insolation [unit = W/m2];
            2.2.1.  EEBC-94 states that SF = 435 W/m2 for roofs; and
            2.2.2.  SF = 372 W/m2 for walls.

2.3       Shading Coefficient (SC) is the ratio of solar heat-gain through any fenestration compared to that through an unshaded, 3-mm thick double-strength glass.

            SC =   Solar Heat-Gain through any fenestration                                              [2.1]
                        Solar Heat-Gain through reference glass


3.0  CALCULATING OTTV OF ROOFS



3.1       EEBC-94 specifies the maximum OTTV for roofs as 20 W/m2 ;

3.2       There are two equations for calculating OTTVs for roofs.
            3.2.1   For roofs without skylights,

            OTTVr =          [DT x Ur] + [(TDeq - DT) x Ac x Ur]                                                    [3.1]

            where,
            OTTVr = Overall Thermal Transmission Value of a roof, W/m2
                        DT       = Temperature Difference, K
                                    = Td - Ti
                        Td        = Design Temperature, C  
                                    = 33.9 C, for Kingston


                        Ti         = Thermostat set-point, C
                        TDeq    =  Equivalent Temperature Differential, K
                        Ac        = Solar absorptance (0<Ac<1)
                        Ur        = Overall Thermal Transmission Coefficient of roof, W/m-K  



Table showing Shading Coefficients for Fenestration
Fig. 1:  Shading Coefficients for Fenestration



            3.2.2   For roofs with skylights,

            OTTVr =          [DT x Ur x (1-SRR)] + [(TDeq - DT) x Ac x Ur x (1-SRR)] +
                                    [DT x Us x SRR] + [SF x SCs x SRR]                                             [3.2]
            where,
                        SRR   = Skylight-to-Roof Ratio (0<SRR<1)
                        SF       = Solar Factor for roof, W/m2
                        SCs     = Shading Coefficient of skylights (0<SCs <1)
                        Us        =  Overall Thermal Transmission Coefficient of roof, W/m-K


4.0  CALCULATING OTTV OF WALLS

4.1       EEBC-94 species the maximum OTTV for walls as (a) 67.7 W/m2 for large offices [Area > 3,700 m2] (b) 61.7 W/m2, for smaller offices and (c) 53.1 W/m2 for other buildings;

4.2       OTTVi for a wall is calculated as follows:

            OTTVi =          [DT x Ui x (1-WWRi)] + [(TDeq - DT) x CFi x Ac x Ui x (1-WWRi)] +
                                    [DT x Uf x WWRi] + [SF x CFi x SCi x WWRi]                               [4.1]
            where,
            OTTVi = Overall Thermal Transmission Value of a wall “i”, W/m2
                        Ui         =  Overall Thermal Transmission Coefficient of wall “i”, W/m-K
                        WWRi = Window-to-Wall Ratio for wall “i” (0<WWRi<1)
                        SF       = Solar Factor for wall, W/m2
                        CFi      = Correction Factor for orientation of wall “i”
                        SCi      = Shading Coefficient of fenestration on wall “i” (0<SCi <1)
                        Uf        =  Overall Thermal Transmission Coefficient of fenestration, W/m-K

4.3       Overall OTTV for walls is calculated as follows:

            OTTVw =         [(A1 x OTTV1 ) + (A2 x OTTV2) +.........+ (Ai  x OTTVi )]                  [4.2]
                                                            (A1 + A2 + ..............+ Ai)
            where,
                        OTTVw = Overall OTTV for walls “1" to “i”
                        Ai         =   Area of wall “i”



5.0  SAMPLE OTTV CALCULATIONS

Calculate the OTTV for an office building constructed as follows:

Location:        Kingston, Jamaica                               Tin                = 24.4 deg.C
Dimensions:    18 m x 18 m x 3.6 m high                    Orientation    = North
Ac(r)               = 0.35                                                 TDeq(r)         = 23.0 deg.C
Ac(w)              = 0.70                                                 TDeq(w)          = 23.0 deg.C
SRR               = 0.01                                                 Ur                 = 1.10 W/m2-K
WWR            = 0.33                                                 Us                 = 5.40 W/m2-K
SCs                = 0.50                                                 Uw                = 3.01 W/m2-K
SCs                = 0.50                                                 Uf                 = 4.60 W/m2-K



            DT       = Td - Tin
Where,
            Td        = Design temperature         = 33.9 deg.C, for Kingston

ˆ          DT       = 33.9 - 24.4  = 9.5 K



(A)         For a roof with skylights,

            OTTVr =          [DT x Ur x (1-SRR)] + [(TDeq(r) - DT) x Ac(r) x Ur x (1-SRR)] +
                                    [DT x Us x SRR] + [SF(r) x SCs x SRR]                                          [5.1]
            where,
                        SF(r)     = Solar Factor for roof         = 435 W/m2, for Jamaica

ˆ          OTTVr =          [9.5 x 1.10 x (1- 0.01)] + [(23.0 - 9.5) x 0.35 x 1.10 x (1- 0.01)] +
                                    [9.5 x 5.4 x 0.01] + [435 x 0.5 x 0.01]
                        =          10.35 + 5.15 + 0.51 + 2.18
                        =          18.2 W/m2


(B)         OTTVi for a wall is as follows:

            OTTVi =          [DT x Ui x (1-WWRi)] + [(TDeq(w) - DT) x CFi x Ac(w) x Ui x (1-WWRi)] +
                                    [DT x Uf x WWRi] + [SF(w) x CFi x SCi x WWRi]                            [5.2]
            where,
                        SF(w)    = Solar Factor for wall         = 372 W/m2, for Jamaica
                        CFi      = Correction Factor for orientation of wall “i”
            CF1     = 0.96, for east wall

ˆ          OTTV1 =         [9.5 x 3.01 x (1 - 0.33)] + [(23.0 - 9.5) x 0.96 x 0.7 x 3.01 x (1 - 0.33) +
                                    [9.5 x 4.60 x 0.33] + [372 x 0.96 x 0.5 x 0.33]
                        =          19.16 + 18.30 + 14.42 + 58.92
                        =          110.8 W/m2


Similarly, CF2           =          1.09, for south wall

ˆ          OTTV2 =         19.16 + 20.77 + 14.42 + 66.90       =          121.3 W/m2

            CF3     =          1.36, for west wall

ˆ          OTTV3 =         19.16 + 25.92 + 14.42 + 83.48       =          143.0 W/m2

            CF4     =          0.58, for north wall

ˆ          OTTV4 =         19.16 + 11.05 + 14.42 + 35.60       =          80.2 W/m2


(C)         Overall OTTV for walls is as follows:

            OTTVw =         [(A1 x OTTV1 ) + (A2 x OTTV2) +.........+ (Ai  x OTTVi )]                  [5.3]
                                                            (A1 + A2 + ..............+ Ai)
Where,
            A1          =  A2    =  A3    =  A4    = 18 x 3.6       = 64.8 m2

ˆ          OTTVw =         [(64.8 x 110.8) + (64.8 x 121.3) + (64.8 x 143.0) + (64.8 x 80.2)]
                                                            (64.8 + 64.8 + 64.8+ 64.8)
                        =          113.8 W/m2

04 September 2010

Waste Disposal: Septic tank, absorption pit, soakaway pit & land drain

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PAUL HAY Capital Projects

www.phcjam.com


Waste Disposal (part 2 of 2)

Author: Paul Hay
e-mail: paul.hay@phcjam.com
profile: http://www.linkedin.com/in/phcjam


1.0  EFFLUENT MAY NEED TREATMENT BEFORE DISPOSAL


1.1      If a public sewage system is available, the main drain shall be directly connected to it.

1.2      If a public sewage system is unavailable, a private sewage system must be provided.

1.3     Where building occupancy is 20 persons or less, effluent may be discharged into an absorption pit or treated in a septic tank before discharge.

1.4      For occupancies in excess of 20 persons, effluent must be treated in a septic tank.

1.5     A septic tank is an enclosed tank within which sewage is digested by anaerobic bacterial action for later discharge into a suitable filter system.
         1.5.1 Scum forms at the top of the inlet tank and sludge settles to the bottom.
         1.5.2 It holds all solid wastes and liquids overflow into outlets.
         1.5.3 The sludge must periodically be removed to avoid filling the tank.
        1.5.4 It should therefore be built in a location that permits cesspool emptiers to park no further than 3m away.

1.6     The capacity of the septic tank shall be determined from local building codes or equivalent to daily water use calculated for the building’s occupants.


Table 1: Minimum required capacity of septic tanks

Table 1: Minimum required capacity of septic tanks

[Source:- National Building Code of Jamaica, 1983]



Figure 1: Typical Septic Tank

Figure 1: Typical Septic Tank


1.7 It should be constructed of reinforced concrete or rendered concrete blocks.
        1.7.1 The effective depth of the tank is taken from the invert of the incoming drain and shall be at least 1.5 m.
       1.7.2 The incoming drain shall be higher than the outgoing drain.
       1.7.3 The width shall be no less than 750 mm.
       1.7.4 In a twin chamber tank, the inlet chamber shall be twice the capacity of the outlet chamber.
       1.7.5 Access should be provided to each chamber by means of manhole covers.


2.0   EFFLUENT NEEDS TO BE SAFELY DISCHARGED


2.1 An absorption pit is the simplest means of discharging effluent.
       2.1.1 It is an underground storage pit within which sewage is digested by anaerobic bacterial action and passes through its walls into the soil.
      2.1.2 It is circular in cross-section with sides lined with stones and tapered inward, such that the bottom is smaller than the top.
      2.1.3 The capacity shall be determined from the local building code.
              2.1.3.1 The effective depth is taken from the invert of the incoming drain and shall be 3 m or more.
              2.1.3.2 The effective diameter shall be taken mid-way the depth.
      2.1.4 The pit shall be located no closer than 30 m from a source of water.
      2.1.5 Bottom of pit shall be 600 mm or more above the watertable.
      2.1.6 The pit shall be covered by a reinforced concrete slab having a manhole cover.


Table 2: Minimum capacities for absorption pits

Table 2: Minimum capacities for absorption pits

[Source:- National Building Code of Jamaica, 1983]


2.2 For building occupancies of 20 persons or below, a septic tank shall be connected to a soak-away pit for disposal.
        2.2.1 A soak-away pit is an underground pit for storage of waste water or effluent from a septic tank which facilitates percolation into the soil.
        2.2.2 It should be located no closer than 30 m from a water source.
        2.2.3 Its capacity shall be equal to that of the septic tank.
        2.2.4 Its effective depth shall be the distance of the invert from the bottom of the excavation.
        2.2.5 It shall be covered with a concrete slab extending pass its sides.

2.3 For building occupancies over 20 persons, a septic tank shall be connected to a land drain.
        2.3.1 A land drain, or tile field, is a layout of underground pipes for the purpose of discharging the effluent of a septic tank into the soil.
        2.3.2 It shall be located no closer than 15 m from a water source.
        2.3.3 The total length of pipes shall be determined from the local building code according to the permeability of the soil.
               2.3.3.1 Perforated pipes or sections of pipes no longer than 600 mm shall be laid in trenches on top of a bed of gully gravel and covered with the gravel.
               2.3.3.2 Trenches shall be at least 450 mm wide by 900 mm deep and no longer than 30 m.

Figure 2: Details of land drains

Figure 2: Details of land drains

[Source:- AIA Architectural Graphic Standards, 1981]

        4.3.4 Where watertable is high, mounds can be used with leaching beds.
                 4.3.4.1 A leaching bed is like a land drain set in a mound instead of trenches for the purpose of discharging the effluent of a septic tank into the soil.
                 4.3.4.2 A pump is required to lift the effluent from a sump to the level of the mound.



Figure 3: Arrangement of land drains on sloping site

Figure 3: Arrangement of land drains on sloping site

[Source:- AIA Architectural Graphic Standards, 1981]


Figure 4: Details of diversion box

Figure 4: Details of diversion box

[Source:- AIA Architectural Graphic Standards, 1981]

               4.3.4.3 The absorption area for the leaching bed is 50% larger than the land drain trenches.
               4.3.4.4 The bottom of the leaching bed shall be higher than 1.5 m above the watertable
      4.3.5 Where soil permeability is less than 25 mm per hour, land drains shall only be used to dispose of effluent from a biological filter

____________________________________________________________________________

FURTHER READING

National Building Code of Jamaica ,2nd edition, Ministry of Finance & Planning, Ja., 1992.
Mechanical and Electrical Equipment for Buildings, 8th edition, Benjamin Stein, John S. Reynolds, John Wiley & Sons Inc., USA, 1992;
Construction Materials & Processes, Don G. Watson, McGrawHill Book Co., USA, 1978;
Ramsey/Sleeper Architectural Graphic Standards, A.I.A., Robert T. Packard (ed), John Wiley & Sons Inc., USA, 1981;